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Re: If 5 < (8 – x)/3, then which of the following MUST be true? I. 3 <
[#permalink]
21 Feb 2022, 06:54
GreenlightTestPrep wrote:
If \(5 < \frac{(8 – x)}{3}\), then which of the following MUST be true?
I. 3 < x II. |x + 4| > 3 III. –(x + 7) is positive
A) II only B) III only C) I and II only D) II and III only E) I, II and III
Given: \(5 < \frac{(8 – x)}{3}\)
Multiply both sides of the inequality by \(3\) to get: \(15 < 8 – x\) Subtract \(8\) from both sides to get: \(7 < -x\) Multiply both sides by \(-1\) to get: \(-7 > x\) [since I multiplied both sides by a NEGATIVE I had to reverse the direction of the inequality symbol. See the video below for more on this.]
Since we now know \(x < -7\), we are ready to check the statements...
I. 3 < x If \(x < -7\), it can't be the case that 3 < x. So, statement I is not true.
II. |x + 4| > 3 If x = -7, then |x + 4| = |(-7) + 4| = |-3| = 3 So, if x is less than -7, then x + 4 will be less than -3, which means |x + 4| will be greater than 3. So, statement II must be true.
III. –(x + 7) is positive If we take \(x < -7\) and... Add 7 to both sides we get: \(x + 7< 0\) Now multiply both sides by (-1) to get: \(-(x + 7)> 0\) So, statement III must be true.
Answer: D
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gmatclubot
Re: If 5 < (8 – x)/3, then which of the following MUST be true? I. 3 < [#permalink]