Carcass wrote:
Ted can finish a job in 3 hours and Ann can finish the same job in 4 hours. If Ted works alone for 1 hour, and then Ann and Ted work together to finish the job, for how many more hours do they have to work together?
(A) 8/7
(B) 6/5
(C) 5/4
(D) 4/3
(E) 3/2
Let they work for \(x\) hours together.
Rate of Ted = \(\frac{1}{3}\), and
Rate of Ann = \(\frac{1}{4}\)
Now, Total work done by both Ted and Ann must be 1
i.e. \(W_T + W_A = 1\)
Since, Work = (Rate)(Time)
We can write the above equation as;
\((R_T)(T_T) + (R_A)(T_A) = 1\)
Now, Ted worked for a total of \((1 + x)\) hours i.e. \(T_T = (1 + x)\)
whereas, Ann worked for a total of \(x\) hours i.e. \(T_A = x\)
\(\frac{1}{3}(1 + x) + \frac{1}{4}(x) = 1\)
\(\frac{1}{3} + \frac{x}{3} + \frac{x}{4} = 1\)
\(\frac{x}{3} + \frac{x}{4} = \frac{2}{3}\)
\(\frac{4x + 3x}{12} = \frac{2}{3}\)
\(\frac{7x}{12} = \frac{2}{3}\)
\(x = \frac{8}{7}\)
Hence, option A