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5 sqrt3x

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Carcass
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5 sqrt3x [#permalink] New post   Updated on: 24 Feb 2022, 10:01
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\(x >0\)

Quantity A
Quantity B
\(5 \sqrt{3x}\)
\(3 \sqrt{5x} \)



A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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A

Originally posted by Carcass on 24 Feb 2022, 08:00.
Last edited by Carcass on 24 Feb 2022, 10:01, edited 1 time in total.
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GreenlightTestPrep
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5 sqrt3x [#permalink] New post   24 Feb 2022, 09:49
Carcass wrote:
\(x >0\)
Quantity A
Quantity B
\(5 \sqrt{3x}\)
\(3 \sqrt{5x} \)



Property: If x and y are positive, and \(0< x^2 < y^2\), then \(0< x < y\)

Given:
Quantity A: \(5 \sqrt{3x}\)
Quantity B: \(3 \sqrt{5x} \)

Square both quantities to get:
Quantity A: \((5 \sqrt{3x})^2\)
Quantity B: \((3 \sqrt{5x})^2\)

Simplify both quantities:
Quantity A: \((25)(3x)\)
Quantity B: \((9)(5x) \)

Simplify more:
Quantity A: \(75x\)
Quantity B: \(45x \)

Since we are told \(x > 0\), we can safely divide both quantities by x to get:
Quantity A: \(75\)
Quantity B: \(45 \)

Answer: A
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gmatclubot
5 sqrt3x [#permalink]
24 Feb 2022, 09:49
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