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A certain kickball team named "The good guys" won 1/3 of their first 2
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19 Dec 2021, 13:05
19 Dec 2021, 13:05
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Question Stats:
50% (02:45) correct
50% (01:37) wrong based on 6 sessions
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A certain kickball team named "The good guys" won 1/3 of their first 24 games. If the teams lose no more than 1/9 of their remaining games, what is the least number of games they must play to ensure they win more than they loose?
a) 9
b) 10
c) 11
d) 12
e) 13
May someone tell me where is my mistake?
I tried solving backward by starting with a
(1/9)∗9+16=17
and the winning will be (8/9)∗9+8=16 option a wrong
no for the rest, all of the options will give us the first option 1.something .. I round it to 2.
Until I reach 13, where the winning games is more than the lost games.
a) 9
b) 10
c) 11
d) 12
e) 13
May someone tell me where is my mistake?
I tried solving backward by starting with a
(1/9)∗9+16=17
and the winning will be (8/9)∗9+8=16 option a wrong
no for the rest, all of the options will give us the first option 1.something .. I round it to 2.
Until I reach 13, where the winning games is more than the lost games.
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Re: A certain kickball team named "The good guys" won 1/3 of their first 2
[#permalink]
04 Mar 2022, 00:58
04 Mar 2022, 00:58
1
Asmakan wrote:
A certain kickball team named "The good guys" won 1/3 of their first 24 games. If the teams lose no more than 1/9 of their remaining games, what is the least number of games they must play to ensure they win more than they loose?
a) 9
b) 10
c) 11
d) 12
e) 13
May someone tell me where is my mistake?
I tried solving backward by starting with a
(1/9)∗9+16=17
and the winning will be (8/9)∗9+8=16 option a wrong
no for the rest, all of the options will give us the first option 1.something .. I round it to 2.
Until I reach 13, where the winning games is more than the lost games.
a) 9
b) 10
c) 11
d) 12
e) 13
May someone tell me where is my mistake?
I tried solving backward by starting with a
(1/9)∗9+16=17
and the winning will be (8/9)∗9+8=16 option a wrong
no for the rest, all of the options will give us the first option 1.something .. I round it to 2.
Until I reach 13, where the winning games is more than the lost games.
Games Won = 13(24)=8
Games Lost = 24−8=16
Let, the total number of remaning games be x
Games Lost of the remaining = x9, and
Games Won of the remaining = x−x9=8x9
As per the question;
Total games Won ≥ Total games Lost
8+8x9≥16+x9
8x9−x9≥8
7x≥72
i.e. x≥10.28
Hence, option C
gmatclubot
Re: A certain kickball team named "The good guys" won 1/3 of their first 2 [#permalink]
04 Mar 2022, 00:58
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