GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
If f(x) = x2 - 9, what is the value of f(3)?
[#permalink]
24 Feb 2022, 07:00
24 Feb 2022, 07:00
Expert Reply
1
Bookmarks
00:00
Question Stats:
68% (00:21) correct
31% (00:31) wrong based on 22 sessions
Hide Show timer Statistics
If \(f(x) =\frac{ x^2 - 9}{x-3}\), what is the value of f(3)?
(A) -6
(B) 0
(C) 1
(D) 6
(E) Undefined
(A) -6
(B) 0
(C) 1
(D) 6
(E) Undefined
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Re: If f(x) = x2 - 9, what is the value of f(3)?
[#permalink]
04 Mar 2022, 23:49
04 Mar 2022, 23:49
1
Carcass wrote:
If \(f(x) =\frac{ x^2 - 9}{x-3}\), what is the value of f(3)?
(A) -6
(B) 0
(C) 1
(D) 6
(E) Undefined
(A) -6
(B) 0
(C) 1
(D) 6
(E) Undefined
Plug x = 3
f(3) = \(\frac{3^2 - 9}{0}\)
Since, the denominator is 0, f(3) is undefined
Hence, option E
Suggestion: DO NOT factorize the function and then solve
Moderator
Joined: 02 Jan 2020
Status:GRE Quant Tutor
Posts: 1141
Given Kudos: 9
Location: India
Concentration: General Management
Schools: XLRI Jamshedpur, India - Class of 2014
GMAT 1: 700 Q51 V31
GPA: 2.8
WE:Engineering (Computer Software)
If f(x) = x2 - 9, what is the value of f(3)?
[#permalink]
07 Aug 2022, 10:25
07 Aug 2022, 10:25
Given that \(f(x) =\frac{ x^2 - 9}{x-3}\) and we need to find the value of f(3)
To find f(3) we need to compare what is inside the bracket in f(3) and f(x)
=> We need to substitute x with 3 in \(f(x) =\frac{ x^2 - 9}{x-3}\) to get the value of f(3)
=> \(f(3) =\frac{ 3^2 - 9}{3-3}\) = \(\frac{9-9}{0}\) = \(\frac{0}{0}\) = Undefined ( as anything divided by 0 is Undefined)
So, Answer will be E
Hope it helps!
Watch the following video to learn the Basics of Functions and Custom Characters
To find f(3) we need to compare what is inside the bracket in f(3) and f(x)
=> We need to substitute x with 3 in \(f(x) =\frac{ x^2 - 9}{x-3}\) to get the value of f(3)
=> \(f(3) =\frac{ 3^2 - 9}{3-3}\) = \(\frac{9-9}{0}\) = \(\frac{0}{0}\) = Undefined ( as anything divided by 0 is Undefined)
So, Answer will be E
Hope it helps!
Watch the following video to learn the Basics of Functions and Custom Characters
