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Retired Moderator
Joined: 16 Apr 2020
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The figure above shows four circles with diameters OA, OB, OC and OD
[#permalink]
11 Mar 2022, 00:50
11 Mar 2022, 00:50
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Question Stats:
100% (02:28) correct
0% (00:00) wrong based on 4 sessions
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Attachment:
Four circles with diameters OA, OB, OC and OD are inscribed in a circle O.png [ 13.72 KiB | Viewed 2221 times ]
The figure above shows four circles with diameters OA, OB, OC and OD inscribed in a circle O.
Quantity A |
Quantity B |
Ratio of Areas of two shaded regions |
1 |
A. The quantity in Column A is greater.
B. The quantity in Column B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Re: The figure above shows four circles with diameters OA, OB, OC and OD
[#permalink]
24 Mar 2022, 23:48
24 Mar 2022, 23:48
1
KarunMendiratta wrote:
Attachment:
Four circles with diameters OA, OB, OC and OD are inscribed in a circle O.png
The figure above shows four circles with diameters OA, OB, OC and OD inscribed in a circle O.
Quantity A |
Quantity B |
Ratio of Areas of two shaded regions |
1 |
A. The quantity in Column A is greater.
B. The quantity in Column B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given
Let the radius of smaller circles be \(r\)
Then, the radius of circle O is \(2r\)
Now, Area of circle O = Area of orange region + 4(Area of smaller circles) - Area of blue region
\(π(2r)^2\) = Area of orange region + 4(\(πr^2\)) - Area of blue region
\(4πr^2 - 4πr^2\) = Area of orange region - Area of blue region
i.e. Area of orange region = Area of blue region
Col. A: 1
Col. B: 1
Col. A = Col. B
Hence, option C
gmatclubot
Re: The figure above shows four circles with diameters OA, OB, OC and OD [#permalink]
24 Mar 2022, 23:48
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