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Re: 2<x<3
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08 Apr 2022, 11:22
Multiply both num and denominator of option A with x -1, we get x+7 * x-1 / x + 1 * x -1 ----> x^2 + 6x - 7 / x^2 -1
Multiply both num and denominator of option B with x +1, we get x+3 * x+1 / x - 1 * x+1 ---> x^2+ 4x + 3 / x^2 -1
Now since, denominator of both options is equal we can just compare the num -----> even x^2 in num can be ignored as it's present in both options.
So finally we have to check relationship 6x - 7 ? 4x + 3
Put 2.5 as a value and we can see option B > option A, hence B is correct ans