Quote:
If S is the sum of the reciprocals of the consecutive integers from 91 to 100, inclusive, which of the following is less than S?
There are 10 consecutive integers from 91 to 100, inclusive
If all 10 integers be 90, then sum of the reciprocals of the consecutive integers = 1/90 *10 = 1/9
If all 10 integers be 100, then sum of the reciprocals of the consecutive integers = 1/100 *10 = 1/10
This means, sum of the reciprocals of the consecutive integers from 91 to 100, inclusive, lies between 1/10 and 1/9
1/10 < S <1/9
Hence, 1/10 is less than S
IMO C