GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
The height of a tree is measured by means of a cross-staff as shown in
[#permalink]
20 Apr 2022, 13:18
20 Apr 2022, 13:18
Expert Reply
1
Bookmarks
00:00
Question Stats:
75% (02:33) correct
25% (02:42) wrong based on 4 sessions
Hide Show timer Statistics
The height of a tree is measured by means of a cross-staff as shown in the figure above. The horizontal bar DE is adjusted up or down until points D, F, and B are in a straight line. Measured on level ground, DE is \(1\frac{1}{2}\) feet, EF is \(\frac{1}{2}\) foot, GE is 5 feet and GA is 60 feet. How tall is the tree?
A. \(20 \frac{1}{2}\) ft.
B. \(22\) ft.
C. \(24\) ft.
D. \(25\frac{1}{2}\) ft.
E. \(26\frac{1}{2}\) ft.
Re: The height of a tree is measured by means of a cross-staff as shown in
[#permalink]
22 Apr 2022, 02:40
22 Apr 2022, 02:40
1
Expert Reply
DE = 1.5 ft
EF = 0.5 ft
GE = 5 ft
GA = 60 ft
Notice that triangle DEF and triangle DBC are similar triangles.
\(\frac{DE}{EF} = \frac{DC}{BC} = \frac{1.5}{0.5} = \frac{61.5}{20.5}\)
\(20.5 + EG = 20.5 + 5 = 25.5 ft\)
Answer is D.
EF = 0.5 ft
GE = 5 ft
GA = 60 ft
Notice that triangle DEF and triangle DBC are similar triangles.
\(\frac{DE}{EF} = \frac{DC}{BC} = \frac{1.5}{0.5} = \frac{61.5}{20.5}\)
\(20.5 + EG = 20.5 + 5 = 25.5 ft\)
Answer is D.
gmatclubot
Re: The height of a tree is measured by means of a cross-staff as shown in [#permalink]
22 Apr 2022, 02:40
Moderators:
