Carcass wrote:
In the sequence \(a_1\), \(a_2\), \(a_3\), …, \(a_n\), \(a_n=a_{n−1}+a_{n−2}\). If \(a_1=1\) and \(a_2=1\), which of the following correctly expresses the first 5 terms of the sequence?
A. 1, 1, 2, 3, 4
B. 1, 1, 2, 3, 5
C. 1, 1, 2, 3, 6
D. 1, 1, 2, 4, 8
E. 1, 2, 3, 4, 5
Given: \(a_n=a_{n−1}+a_{n−2}\)
So, \(a_3=a_{3−1}+a_{3−2}=a_{2}+a_{1} = 1 + 1 = 2\)
Similarly, \(a_4=a_{3}+a_{2} = 2 + 1 = 3\)
And, \(a_5=a_{4}+a_{3} = 3 + 2 = 5\)
So, the first five terms are: \(1, 1, 2, 3, 5\)
Answer: B