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1 < a < b < 0
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06 May 2022, 01:18
06 May 2022, 01:18
Expert Reply
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Question Stats:
75% (00:41) correct
25% (00:29) wrong based on 20 sessions
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\(− 1 < a < b < 0\)
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
\(a+b\) |
\( a-b\) |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Part of the project: GRE Quantitative Comparison & Problem Solving Challenge
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
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Re: 1 < a < b < 0
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06 May 2022, 06:16
06 May 2022, 06:16
1
Carcass wrote:
\(− 1 < a < b < 0\)
Quantity A |
Quantity B |
\(a+b\) |
\( a-b\) |
We can solve this question using matching operations (see the video lesson below )
Given:
Quantity A: \(a+b\)
Quantity B: \( a-b\)
Add \(b\) to both quantities:
Quantity A: \(a+2b\)
Quantity B: \( a\)
Subtract \(a\) from both quantities:
Quantity A: \(2b\)
Quantity B: \(0\)
Since it's given that \(b\) is negative, we can conclude that \(2b\) is negative, which means Quantity B is greater.
Answer: B
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gmatclubot
Re: 1 < a < b < 0 [#permalink]
06 May 2022, 06:16
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