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xy < 0
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20 May 2022, 08:55
20 May 2022, 08:55
Expert Reply
00:00
Question Stats:
85% (00:37) correct
14% (00:10) wrong based on 7 sessions
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\(xy < 0\)
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
\( [x+y]^2\) |
\( x^2+y^2\) |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022)
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GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
Re: xy < 0
[#permalink]
20 May 2022, 10:05
20 May 2022, 10:05
1
Expanding [x+y]^2 = x^2+2xy+y^2
Since xy<0, quantity a will always have the effect of negative 2xy
Therefore quantity B will be greater
Answer is (B)
Since xy<0, quantity a will always have the effect of negative 2xy
Therefore quantity B will be greater
Answer is (B)
Re: xy < 0
[#permalink]
21 May 2022, 03:17
21 May 2022, 03:17
1
Quick and swift.
Simplify the two quantities, and cancel common terms from both sides, yielding:
Quantity A: 2xy
Quantity B: 0.
Given that xy < 0. Hence A is negative, and B is positive. Hence B is greater.
Simplify the two quantities, and cancel common terms from both sides, yielding:
Quantity A: 2xy
Quantity B: 0.
Given that xy < 0. Hence A is negative, and B is positive. Hence B is greater.
