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xy < 0 [#permalink] New post   20 May 2022, 08:55
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Question Stats:

85% (00:37) correct 14% (00:10) wrong based on 7 sessions

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\(xy < 0\)

Quantity A
Quantity B
\( [x+y]^2\)
\( x^2+y^2\)



A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

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B
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B
alsafaj
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Re: xy < 0 [#permalink] New post   20 May 2022, 10:05
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Expanding [x+y]^2 = x^2+2xy+y^2

Since xy<0, quantity a will always have the effect of negative 2xy

Therefore quantity B will be greater
Answer is (B)
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Re: xy < 0 [#permalink] New post   21 May 2022, 03:17
1
Quick and swift.

Simplify the two quantities, and cancel common terms from both sides, yielding:

Quantity A: 2xy
Quantity B: 0.

Given that xy < 0. Hence A is negative, and B is positive. Hence B is greater.
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gmatclubot
Re: xy < 0 [#permalink]
21 May 2022, 03:17
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