Carcass wrote:
Abdul, Barb, and Carlos all live on the same straight road, on which their school is also located. The school is halfway between Abdul’s house and Barb’s house. Barb’s house is halfway between the school and Carlos’s house. If the school is 4 miles from Carlos’s house, how many miles is Abdul’s house from Carlos’s house?
A. \(1\frac{1}{3}\)
B. 2
C. 4
D. 6
E. 8
The school is halfway between Abdul’s house and Barb’s house. Sketch it to get:
A--------
S--------
BAside: The distances between A and S and between S and B are EQUAL
Barb’s house is halfway between the school and Carlos’s house. Add Carlos's house to drawing:
A--------
S--------
B--------
CAside: All 3 distances are EQUAL
If the school is 4 miles from Carlos’s house...A--------
S--------B--------CSo, the two
RED distances add to 4 miles
Since those two distances are EQUAL, each distance must equal 2 miles.
That is:
A----2miles----
S----2miles----
B----2miles----
C...how many miles is Abdul’s house from Carlos’s house?The distance = 6 miles
Answer: D