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a>b>c>d>0

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Carcass
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a>b>c>d>0 [#permalink] New post   19 Jun 2022, 23:44
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\(a>b>c>d>0\)


Quantity A
Quantity B
a-d
b-c


A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

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A
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GreenlightTestPrep
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Re: a>b>c>d>0 [#permalink] New post   20 Jun 2022, 05:54
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Carcass wrote:
\(a>b>c>d>0\)

Quantity A
Quantity B
a-d
b-c




There are a few different ways to solve this question.

Approach #1: Number sense
Since \(a>b>c>d>0\), we can see that the difference \(a-d\) must be greater than the difference \(b-c\)
Answer: A

Approach #2: Matching operations

Given:
QUANTITY A: \(a-d\)
QUANTITY B: \(b-c\)

Add \(d\) to both quantities:
QUANTITY A: \(a\)
QUANTITY B: \(b-c+d\)

Add \(c\) to both quantities:
QUANTITY A: \(a+c\)
QUANTITY B: \(b+d\)

Since \(a>b\) and \(c>d\), we can add the two inequalities to get: \(a+c > b + d\)

Answer: A
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Re: a>b>c>d>0 [#permalink] New post   23 Jul 2023, 18:43
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We can also solve the problem using number line. a is put on the right-most, while d is put on the left-most. a-d means the distance between a and d. Hence, a-d > b-c.
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Re: a>b>c>d>0 [#permalink] New post   05 Sep 2024, 04:01
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: a>b>c>d>0 [#permalink]
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