There are a few different ways to solve this question.

Approach #1: Number sense
Since \(a>b>c>d>0\), we can see that the difference \(a-d\) must be greater than the difference \(b-c\)
Answer: A

Approach #2: Matching operations

Given:
QUANTITY A: \(a-d\)
QUANTITY B: \(b-c\)

Add \(d\) to both quantities:
QUANTITY A: \(a\)
QUANTITY B: \(b-c+d\)

Add \(c\) to both quantities:
QUANTITY A: \(a+c\)
QUANTITY B: \(b+d\)

Since \(a>b\) and \(c>d\), we can add the two inequalities to get: \(a+c > b + d\)

Answer: A
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We can also solve the problem using number line. a is put on the right-most, while d is put on the left-most. a-d means the distance between a and d. Hence, a-d > b-c.