Carcass wrote:
\(a>b>c>d>0\)
Quantity A |
Quantity B |
a-d |
b-c |
There are a few different ways to solve this question.
Approach #1: Number sense
Since \(a>b>c>d>0\), we can see that the difference \(a-d\) must be greater than the difference \(b-c\)
Answer: AApproach #2: Matching operations
Given:
QUANTITY A: \(a-d\)
QUANTITY B: \(b-c\)
Add \(d\) to both quantities:
QUANTITY A: \(a\)
QUANTITY B: \(b-c+d\)
Add \(c\) to both quantities:
QUANTITY A: \(a+c\)
QUANTITY B: \(b+d\)
Since \(a>b\) and \(c>d\), we can add the two inequalities to get: \(a+c > b + d\)
Answer: A