Carcass wrote:
Carla has \(\frac{1}{4}\) more sweaters than cardigans, and \(\frac{2}{5}\) fewer cardigans than turtle necks. If she has at least one of each item, what is the minimum total number of turtlenecks plus sweaters that Carla could have?
Given
S = \((\frac{1}{4} +1)*C\)
= \((\frac{5}{4})*C\)
and C = \((1-\frac{2}{5} )*T\)
= \((\frac{3}{5})*T\)
or T = \((\frac{5}{3})*C\)
Now
Let C = 12 (since it is a factor of 4 and 3. It should be the minimum value)
therefore S= \((\frac{5}{4})*12\)
or S = 15
and T =\((\frac{5}{3})*12\)
or T = 20
Therefore the sweater and turtle neck = 15+20 =35