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A purse contains 5-cent coins and 10-cent coins
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20 Jul 2022, 09:38
20 Jul 2022, 09:38
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Question Stats:
100% (02:56) correct
0% (00:00) wrong based on 2 sessions
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A purse contains 5-cent coins and 10-cent coins worth a total of $1.75. If the 5-cent coins were replaced with 10-cent coins and the 10-cent coins were replaced with 5-cent coins, the coins would be worth a total of $2.15. How many coins are in the purse?
(A) 26
(B) 27
(C) 28
(D) 29
(E) 30
(A) 26
(B) 27
(C) 28
(D) 29
(E) 30
Re: A purse contains 5-cent coins and 10-cent coins
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20 Jul 2022, 09:43
20 Jul 2022, 09:43
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Solution -
Let the number of 5 cent coins be a and the number of 10 cent coins be b
We have been given that 5a + 10b = 175 (total value in cents)
On reversing the numbers we get 5b + 10a = 215 (total value in cents)
Add both the equations to get 15(a + b) = 390
Therefore, a + b = 26
Answer Choice - A
Let the number of 5 cent coins be a and the number of 10 cent coins be b
We have been given that 5a + 10b = 175 (total value in cents)
On reversing the numbers we get 5b + 10a = 215 (total value in cents)
Add both the equations to get 15(a + b) = 390
Therefore, a + b = 26
Answer Choice - A
gmatclubot
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20 Jul 2022, 09:43
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