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Peter left home and drove toward the family vacation house at an ave

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Peter left home and drove toward the family vacation house at an ave [#permalink] New post   04 Aug 2022, 02:55
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Peter left home and drove toward the family vacation house at an average speed of 40 km/hour. Sophia left home some time later and, driving at 48 km/hr for five hours, caught up with Peter. At that time Peter had been driving for h hours.

Quantity A
Quantity B
336 km
The distance Sophia could drive in h hours at her current speed



A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

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Peter left home and drove toward the family vacation house at an ave [#permalink] New post   04 Aug 2022, 13:38
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Carcass wrote:
Peter left home and drove toward the family vacation house at an average speed of 40 km/hour. Sophia left home some time later and, driving at 48 km/hr for five hours, caught up with Peter. At that time Peter had been driving for h hours.

Quantity A
Quantity B
336 km
The distance Sophia could drive in h hours at her current speed



A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given





Peter's velocity: 40 km/h
Sophia's velocity : 48 km/h

hours driven by Peter: x
hours driven by Sophia: 5

Due to the fact that Sofia caught up with Peter at the same distance, we can set up the following euation:

48*5 = 40*x

with x= 6. Thus, we can calculate the distance that Sophia would have traveled if she had spent the same time that Peter spent travelling. It can be done by multiplying her velocity by the time Peter spent: 6*48 = 288.

A > B
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Peter left home and drove toward the family vacation house at an ave [#permalink] New post   12 Jan 2024, 03:12
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As peter and Sophia met thus we can solve it by suing relative speed.

as Sophia need to drive for 5 hours to meet peter thus we can say after 5 hrs they both met.

Time = distance between two peter and Sophia / speed of Sophia - speed of peter

5 = 40 * (h-5) / 8

40 * (h-5) is distance between two peter and Sophia, D= S*T , S=40 by which peter is travelling , Time for which peter travel alone at starting is (h-5)

h= 6 hours

distance Sophia could drive in h hours at her current speed = 6 *48 =288
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Peter left home and drove toward the family vacation house at an ave [#permalink]
12 Jan 2024, 03:12
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