Carcass wrote:
Peter left home and drove toward the family vacation house at an average speed of 40 km/hour. Sophia left home some time later and, driving at 48 km/hr for five hours, caught up with Peter. At that time Peter had been driving for h hours.
Quantity A |
Quantity B |
336 km |
The distance Sophia could drive in h hours at her current speed |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Peter's velocity: 40 km/h
Sophia's velocity : 48 km/h
hours driven by Peter: x
hours driven by Sophia: 5
Due to the fact that Sofia caught up with Peter at the same distance, we can set up the following euation:
48*5 = 40*x
with x= 6. Thus, we can calculate the distance that Sophia would have traveled if she had spent the same time that Peter spent travelling. It can be done by multiplying her velocity by the time Peter spent: 6*48 = 288.
A > B