Last visit was: 15 Nov 2024, 08:47 It is currently 15 Nov 2024, 08:47

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Verbal Expert
Joined: 18 Apr 2015
Posts: 29961
Own Kudos [?]: 36231 [1]
Given Kudos: 25905
Send PM
Intern
Intern
Joined: 11 Jun 2022
Posts: 38
Own Kudos [?]: 25 [0]
Given Kudos: 187
Send PM
Verbal Expert
Joined: 18 Apr 2015
Posts: 29961
Own Kudos [?]: 36231 [0]
Given Kudos: 25905
Send PM
Verbal Expert
Joined: 18 Apr 2015
Posts: 29961
Own Kudos [?]: 36231 [0]
Given Kudos: 25905
Send PM
x^2k/x^4 or x^k/2 [#permalink]
Expert Reply
Tricky question. We do not know anything about K and x could be anything also. The variation of the values could be also infinite

D is the answer.

However, even picking numbers, the solution is straight and D as well

Suppose K=0 and X=1

A is 1/1 and B is 1. So C is the answer

BUT

K=1
x=1

A is \(\frac{2^2}{2^4} = \frac{1}{2^2}=\frac{1}{4}=0.25\)

B is \(2^{\frac{1}{2}}=\sqrt{2}=1.4\)

B is the answer

Two conflict answers

D is the final pick
Intern
Intern
Joined: 11 Jun 2022
Posts: 38
Own Kudos [?]: 25 [1]
Given Kudos: 187
Send PM
Re: x^2k/x^4 or x^k/2 [#permalink]
1
Carcass wrote:
Fixed question because the same documents, after reviewing, one version is with x>0 that has a logic and one not.

I fixed


Thank you Carcass. That was precisely what was creating confusion as the test cases were not conclusive.
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12189 [2]
Given Kudos: 136
Send PM
Re: x^2k/x^4 or x^k/2 [#permalink]
2
Carcass wrote:
\(x>0\)

Quantity A
Quantity B
\(\frac{x^{2k}}{x^4 }\)
\(x^{\frac{k}{2}}\)



A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given


This question is perfectly suited for a strategy called "Looking for Equality" (see video below)
When I see a quantitative comparison question with variables, I ask myself "Are there obvious values that make the two quantities equal?"
Here, the answer is a big YES.

If \(x = 1\), then regardless of the value of k, the two quantities will be equal
So, I already know that the answer will be either C or D.

From this point it's just a matter of testing another set of values.
For example, if \(x = 10\) and \(k = 2\), then we get:
QUANTITY A: \(\frac{x^{2k}}{x^4 } = \frac{10^{4}}{10^4} = 1\)

QUANTITY B: \(x^{\frac{k}{2}} = 10^{\frac{2}{2}} = 10^1 = 10\)

Here Quantity B is greater

Answer: D

RELATED VIDEO:
Prep Club for GRE Bot
Re: x^2k/x^4 or x^k/2 [#permalink]
Moderators:
GRE Instructor
78 posts
GRE Forum Moderator
37 posts
Moderator
1111 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne