SeaOyster1 wrote:
Box A has 10 green balls and 8 black balls.
Box B has 9 green balls and 5 black balls.
What is the probability if one ball is drawn from each box that both balls are green?
(A) 5/9
(B) 19/252
(C) 10/49
(D) 5/14
(E) 9/14
Total balls in box A - 18
Total balls in box B - 14
Prob. of picking a green ball from box A =
1018=59Prob. of picking a green ball from box B =
914Prob. of picking both the balls together =
(59)(914)=514Hence, option D