Carcass wrote:
What is the least positive integer which when divided by 2, 3, 4, 5 and 6 leaves 1, 2, 3, 4 and 5 as remainders, respectively, but when divided by 7 leaves no remainder ?
(A) 109
(B) 119
(C) 126
(D) 154
(E) 210
Let's deal with each piece of information individually.
We are told that, when the number is divided by 2, the remainder is 1.
This tells us that the number must be ODD, which means we can eliminate answer choices C, D and E they are all EVEN.
We're also told that, when the number is divided by 7, the reminder is 0.
In other words, the number must be divisible by 7.
Let's check the two remaining answer choices...
109 is NOT divisible by 7, which means we can eliminate answer choice A.
119 IS divisible by 7, so the correct answer must be B.