Re: Pat's watch gains an extra 10 seconds every 2 hours. Kim's watch loses
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23 Dec 2022, 04:49
First we have to bring everything to the same scale, to make life easier:
\(10 sec ->2h = 5 sec -> 1h\)
\(5 sec->3h = \frac{5}{3}sec->1h\)
Pat's watch will gain a total of \(5 sec * 72 h = 360 sec\)
Kim's watch will lose a total of\(5/3 sec * 72 h = 120 sec\)
<----------------|-------------------->
(-120sec)----- 0------------( +360 sec)
tot distance = \(120+360=480 sec = 8 min\)
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