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If k is an odd integer, which of the following must be an ev
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26 Nov 2017, 09:14
26 Nov 2017, 09:14
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Question Stats:
92% (00:40) correct
7% (00:41) wrong based on 14 sessions
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If k is an odd integer, which of the following must be an even integer?
A. \(k^2 – 4\)
B. \(3k + 2\)
C. \(2k + 1\)
D. \(\frac{12k}{8}\)
E. \(\frac{6k}{3}\)
Kudos for correct solution.
A. \(k^2 – 4\)
B. \(3k + 2\)
C. \(2k + 1\)
D. \(\frac{12k}{8}\)
E. \(\frac{6k}{3}\)
Kudos for correct solution.
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Re: If k is an odd integer, which of the following must be an ev
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30 Nov 2017, 15:59
30 Nov 2017, 15:59
2
Bunuel wrote:
If k is an odd integer, which of the following must be an even integer?
A. k² – 4
B. 3k + 2
C. 2k + 1
D. 12k/8
E. 6k/3
Kudos for correct solution.
A. k² – 4
B. 3k + 2
C. 2k + 1
D. 12k/8
E. 6k/3
Kudos for correct solution.
The key word in must, which means the correct answer will yield an EVEN value for ALL odd values of k.
So, if we find an odd value for k that does NOT yield an even output, then we can eliminate that answer choice.
Let's see what happens when k = 1 (1 is a nice odd integer to work with)
Plug k = 1 to get...
A. 1² – 4 = -3. -3 is NOT even. ELIMINATE A
B. 3(1) + 2 = 5. 5 is NOT even. ELIMINATE B
C. 2(1) + 1 = 3. 3 is NOT even. ELIMINATE C
D. 12(1)/8 = 3/2. 3/2 is NOT even. ELIMINATE D
By the process of elimination, the correct answer must be E
Cheers,
Brent
If k is an odd integer, which of the following must be an ev
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27 Oct 2018, 16:24
27 Oct 2018, 16:24
Expert Reply
If k is an odd integer, which of the following must be an even integer?
A. \(k^2 – 4\)
B. \(3k + 2\)
C. \(2k + 1\)
D. \(\frac{12k}{8}\)
E. \(\frac{6k}{3}\)
A. \(k^2 – 4\)
B. \(3k + 2\)
C. \(2k + 1\)
D. \(\frac{12k}{8}\)
E. \(\frac{6k}{3}\)
