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Joseph went to buy at least one of each of cake, cookie
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Updated on: 28 Apr 2023, 02:19
Updated on: 28 Apr 2023, 02:19
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Joseph went to buy at least one of each of cake, cookie & donut costing $5, $6 & $10 respectively. If he needs to spend any amount between $30 & $36, both inclusive, in how many ways he can purchase the items?
a) 2
b) 3
c) 4
d) 5
e) more than 5
a) 2
b) 3
c) 4
d) 5
e) more than 5
Originally posted by thelastzedi on 28 Apr 2023, 01:11.
Last edited by Carcass on 28 Apr 2023, 02:19, edited 1 time in total.
Last edited by Carcass on 28 Apr 2023, 02:19, edited 1 time in total.
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Re: Joseph went to buy at least one of each of cake, cookie
[#permalink]
29 Apr 2023, 23:31
29 Apr 2023, 23:31
1
Given that Joseph went to buy at least one of each of cake, cookie & donut costing $5, $6 & $10 respectively and he needs to spend any amount between $30 & $36, both inclusive. And we need to find in how many ways he can purchase the items
Given that he has to buy at least one of each
=> Total amount spent on buying one cake, one cookie and one donut = $5 + $6 + $10 = $21
He has spend between $30 and $36 inclusive
=> Money left to be spent is in between $30 - $21 and $36 - $21 inclusive = $9 and $15 inclusive
Following are the cases possible
Only cake cases
1 cake (not possible) as it will be on $5 and we need to spend between $9 and $15 inclusive
(1) 2 cakes => Money spent = 2 * $5 = $10
(2) 3 cakes => Money spent = $15
only cookie cases
1 cookie (not possible) as it will be on $6 and we need to spend between $9 and $15 inclusive
(3) 2 cookies => Money spent = 2 * $6 = $12
3 cookies (not possible) as it will be on $18 and we need to spend between $9 and $15 inclusive
only donut cases
(4) 1 donut => Money spent = $10
2 donuts (not possible) as it will be on $20 and we need to spend between $9 and $15 inclusive
Cake + Cookie
(5) 1 cake + 1 cookie = $5 + $6 = $11
Other cases not possible as sum will cross $15
Cake + Donut
(6) 1 cake + 1 donut = $5 + $10 = $15
Other cases not possible as sum will cross $15
Cookie + Donut
Not possible as 1 cookie + 1 donut will cost $6 + $10 = $16
=> Totally 6 choices.
So, Answer will be E
Hope it helps!
Given that he has to buy at least one of each
=> Total amount spent on buying one cake, one cookie and one donut = $5 + $6 + $10 = $21
He has spend between $30 and $36 inclusive
=> Money left to be spent is in between $30 - $21 and $36 - $21 inclusive = $9 and $15 inclusive
Following are the cases possible
Only cake cases
1 cake (not possible) as it will be on $5 and we need to spend between $9 and $15 inclusive
(1) 2 cakes => Money spent = 2 * $5 = $10
(2) 3 cakes => Money spent = $15
only cookie cases
1 cookie (not possible) as it will be on $6 and we need to spend between $9 and $15 inclusive
(3) 2 cookies => Money spent = 2 * $6 = $12
3 cookies (not possible) as it will be on $18 and we need to spend between $9 and $15 inclusive
only donut cases
(4) 1 donut => Money spent = $10
2 donuts (not possible) as it will be on $20 and we need to spend between $9 and $15 inclusive
Cake + Cookie
(5) 1 cake + 1 cookie = $5 + $6 = $11
Other cases not possible as sum will cross $15
Cake + Donut
(6) 1 cake + 1 donut = $5 + $10 = $15
Other cases not possible as sum will cross $15
Cookie + Donut
Not possible as 1 cookie + 1 donut will cost $6 + $10 = $16
=> Totally 6 choices.
So, Answer will be E
Hope it helps!
General Discussion
Re: Joseph went to buy at least one of each of cake, cookie
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28 Apr 2023, 02:20
28 Apr 2023, 02:20
Expert Reply
Follow the rules for posting, they are mandatory https://gre.myprepclub.com/forum/rules- ... -1083.html
Add the OA
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Add the OA
Thank you
