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At a church prayer, 3/5 of the members weremales
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29 Oct 2023, 23:11
29 Oct 2023, 23:11
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At a church prayer, 3/5 of the members were males and 3/5 of the male members attendedthe prayer. If 7/10 of the female members attended the prayer, what fraction of the members who did not attend the prayer are males?
A. 1/4
B. 3/7
C. 2/3
D. 9/10
E. 6/19
A. 1/4
B. 3/7
C. 2/3
D. 9/10
E. 6/19
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At a church prayer, 3/5 of the members weremales
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02 Dec 2023, 09:12
02 Dec 2023, 09:12
1
Say x = total number of church members.
\(\frac{3}{5}x \) = total male members, so \((1-\frac{3}{5})*\frac{3}{5}x = \frac{6}{25}x \) = number of male members who did NOT go to church.
\((1-\frac{3}{5})x = \frac{2}{5}x\) = total female members, so \((\frac{2}{5})(1-\frac{7}{10}x) = \frac{6}{50}x = \frac{3}{25} \)= number of female members who did NOT go to church.
The fraction of male members who did not attend out of all of the members who did not attend =
\(\frac{6}{25}x / (\frac{6}{25}x + \frac{3}{25}x)\)
= 6/9 = 2/3
\(\frac{3}{5}x \) = total male members, so \((1-\frac{3}{5})*\frac{3}{5}x = \frac{6}{25}x \) = number of male members who did NOT go to church.
\((1-\frac{3}{5})x = \frac{2}{5}x\) = total female members, so \((\frac{2}{5})(1-\frac{7}{10}x) = \frac{6}{50}x = \frac{3}{25} \)= number of female members who did NOT go to church.
The fraction of male members who did not attend out of all of the members who did not attend =
\(\frac{6}{25}x / (\frac{6}{25}x + \frac{3}{25}x)\)
= 6/9 = 2/3
gmatclubot
At a church prayer, 3/5 of the members weremales [#permalink]
02 Dec 2023, 09:12
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