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For all positive integers n greater than 1, let >n be the total numbe
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Updated on: 29 Dec 2024, 07:24
Updated on: 29 Dec 2024, 07:24
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5% (02:00) correct
94% (00:58) wrong based on 39 sessions
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For all positive integers n greater than 1, let >n be the total number of all the prime numbers from 1 to n. For example, >15 = 6 because there are a total of 6 prime numbers of 15: 2, 3, 5, 7, 11, and 13.
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
>97 |
(>105) - 2 |
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: For all positive integers n greater than 1, let >n be the total numbe
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10 Mar 2022, 16:35
10 Mar 2022, 16:35
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You just have to determine how many prime numbers are between 97 and 105.
Since there are 2; 101 and 103, then the total prime numbers will be the same for both quantities.
Since there are 2; 101 and 103, then the total prime numbers will be the same for both quantities.
Re: For all positive integers n greater than 1, let >n be the total numbe
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29 Dec 2024, 06:57
29 Dec 2024, 06:57
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Carcass will the answer not be B? because 97 is also a prime number that will be included in >105 but not in >97
so >105 has 3 more prime numbers, hence b is greater
so >105 has 3 more prime numbers, hence b is greater
