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Joined: 10 Apr 2015
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What is the remainder when [m]3^{32}[/m] is divided by 82?
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23 Feb 2020, 08:56
23 Feb 2020, 08:56
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Question Stats:
52% (01:45) correct
47% (01:40) wrong based on 59 sessions
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What is the remainder when \(3^{32}\) is divided by \(82\)?
A) 0
B) 1
C) 8
D) 9
E) 81
A) 0
B) 1
C) 8
D) 9
E) 81
Re: What is the remainder when [m]3^{32}[/m] is divided by 82?
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23 Feb 2020, 11:11
23 Feb 2020, 11:11
Expert Reply
Good question but I am a witness of the eras: true I am old.
ten years ago a similar question for the gmat or gre was super tough. Now , if you do your home work, it is moderate
See the patter, no need fancy calculations
\(3^2=9\)
\(3^3=27\) (here what count for us is the unit digit = 7
\(3^4=..1\)
\(3^5=..3\)
\(3^6=..9\)
So the patter before to repeat itself is 9-7-1-3-9. We do need the 32nd position7 which is 7
7 divided by 2 (82 we care only of the unit digit) = 1
B is the answer
ten years ago a similar question for the gmat or gre was super tough. Now , if you do your home work, it is moderate
See the patter, no need fancy calculations
\(3^2=9\)
\(3^3=27\) (here what count for us is the unit digit = 7
\(3^4=..1\)
\(3^5=..3\)
\(3^6=..9\)
So the patter before to repeat itself is 9-7-1-3-9. We do need the 32nd position7 which is 7
7 divided by 2 (82 we care only of the unit digit) = 1
B is the answer
Re: What is the remainder when [m]3^{32}[/m] is divided by 82?
[#permalink]
23 Feb 2020, 11:17
23 Feb 2020, 11:17
Why 7 is divided by 2? please explain
