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A bag contains 3 yellow and 5 blue equally sized marbles. Tw
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17 Apr 2020, 10:51
17 Apr 2020, 10:51
Expert Reply
00:00
Question Stats:
76% (00:53) correct
23% (01:02) wrong based on 21 sessions
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A bag contains 3 yellow and 5 blue equally sized marbles. Two marbles are randomly removed from the bag. What is the probability that 3 yellow and 3 blue marbles remain in the bag?
Show: :: OA
\(\frac{5}{14}\)
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Re: A bag contains 3 yellow and 5 blue equally sized marbles. Tw
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17 Apr 2020, 11:03
17 Apr 2020, 11:03
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Carcass wrote:
A bag contains 3 yellow and 5 blue equally sized marbles. Two marbles are randomly removed from the bag. What is the probability that 3 yellow and 3 blue marbles remain in the bag?
Show: :: OA
\(\frac{5}{14}\)
P(3 yellow and 3 blue marbles REMAIN) = P(2 blue marbles are REMOVED)
= P(1st marble is blue AND 2nd marble is blue)
= P(1st marble is blue) x P(2nd marble is blue)
= 5/8 x 4/7
= 20/56
= 5/14
Answer: 5/14
Cheers,
Brent
Re: A bag contains 3 yellow and 5 blue equally sized marbles. Tw
[#permalink]
12 Jun 2020, 02:05
12 Jun 2020, 02:05
I dont understand the solution sorry 
It says 3 yellow marbles have to remain in bag, and there are already 3 yellows so we dont have to calculate or add any yellow marble? As i can see the solution for only blue marbles
It says 3 yellow marbles have to remain in bag, and there are already 3 yellows so we dont have to calculate or add any yellow marble? As i can see the solution for only blue marbles
