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In the figure below, three circles of radius 1 are tangent t
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25 Jan 2017, 08:37
25 Jan 2017, 08:37
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In the figure below, three circles of radius 1 are tangent to one another. What is the area of the shaded region between them ?
A) π/2 - \(\sqrt{3}\)
B) 1.5
C) π - \(\sqrt{3}\)
D) \(\sqrt{3}\) - π/2
E) 2 - π/2
and I'm using this idea to find the answer, however I'm wondering is there any other way than below to find the answer??
Area of Arc = Θ/360 π r^2
= 60/360 π 1^2
= 1/6 π
3 area of arc = 3 (1/6 π)
= 3/6 π
= 1/2 π
since radius = 1, one of side of Equilateral triangle = 2
Equilateral triangle = √3/4 side^2
= √3/4 2^2
= 4√3/4
= √3
Area of shade = Equilateral triangle - 3 area of arc
= √3 - 1/2 π
A) π/2 - \(\sqrt{3}\)
B) 1.5
C) π - \(\sqrt{3}\)
D) \(\sqrt{3}\) - π/2
E) 2 - π/2
and I'm using this idea to find the answer, however I'm wondering is there any other way than below to find the answer??
Area of Arc = Θ/360 π r^2
= 60/360 π 1^2
= 1/6 π
3 area of arc = 3 (1/6 π)
= 3/6 π
= 1/2 π
since radius = 1, one of side of Equilateral triangle = 2
Equilateral triangle = √3/4 side^2
= √3/4 2^2
= 4√3/4
= √3
Area of shade = Equilateral triangle - 3 area of arc
= √3 - 1/2 π
Re: In the figure below, three circles of radius 1 are tangent t
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26 Jan 2017, 03:03
26 Jan 2017, 03:03
Expert Reply
Please format properly the question next time. Follow the rules. Screen shots are not the best way to deal with.
Thank you so much for your collaboration here on the board.
Thank you
Thank you so much for your collaboration here on the board.
Thank you
Re: In the figure below, three circles of radius 1 are tangent t
[#permalink]
26 Jan 2017, 04:27
26 Jan 2017, 04:27
Carcass wrote:
Please format properly the question next time. Follow the rules. Screen shots are not the best way to deal with.
Thank you so much for your collaboration here on the board.
Thank you
Thank you so much for your collaboration here on the board.
Thank you
Sorry, are you mean thread topic?? Or do you I have to type out the question instead using the screenshot??
