Last visit was: 30 Oct 2024, 09:33 It is currently 30 Oct 2024, 09:33

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2508
Own Kudos [?]: 3553 [7]
Given Kudos: 1053
GPA: 3.39
Send PM
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Own Kudos [?]: 3199 [2]
Given Kudos: 172
Location: India
WE:Education (Education)
Send PM
Manager
Manager
Joined: 11 Oct 2023
Posts: 69
Own Kudos [?]: 44 [1]
Given Kudos: 25
Send PM
Intern
Intern
Joined: 01 Sep 2024
Posts: 6
Own Kudos [?]: 2 [1]
Given Kudos: 48
Send PM
Jeramiah invests his savings of $120,000 by dividing it between two in [#permalink]
1
KarunMendiratta wrote:
GeminiHeat wrote:
Jeramiah invests his savings of $120,000 by dividing it between two interest-earning accounts. He puts 3/4 of his savings in an account that earns lower interest and 1/4 of his savings in an account that earns higher interest. He has no other accounts that earn interest and he makes $3,636 in interest by the end of the year. If one account earns 2 percent annual interest, and both accounts are compounded semiannually, what percent interest does the other account earn?

A. 3

B. 4

C. 5

D. 6

E. 7


\(C.I = P(1 + \frac{r}{100n})^{nt} - P\)

Don't worry we will not be using this formula!

Let us solve this using S.I

\($120,000\) is divided into two Principals of \($90,000\) (with lower rate of interest) and \($30,000\) (with higher rate of interest)

Notice, the option choices are all greater than \(2\)%
This means, \($90,000\) was invested at an interest rate of \(2\)%
So, S.I \(= \frac{(90,000)(2)(1)}{100} = $1800\)

Now, \($30,000\) must give us a return of \(3636- 1800 = $1826\) at \(r\)% rate of interest in a year
i.e. \(1836 = \frac{(30,000)(r)(1)}{100}\)
\(r = 6.12\)%

Hence, option D


Is it actually okay to apply SI in this case if it's semi compounded annually? I thought it it's okay to apply SI for the first year (given it's compounded annually)
Prep Club for GRE Bot
Jeramiah invests his savings of $120,000 by dividing it between two in [#permalink]
Moderators:
GRE Instructor
77 posts
GRE Forum Moderator
37 posts
Moderator
1111 posts
GRE Instructor
222 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne