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Which of the following must be greater than x, where -1 < x

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Bunuel
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Which of the following must be greater than x, where -1 < x [#permalink] New post   29 Oct 2017, 01:23
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Which of the following must be greater than x, where -1 < x < 0?

Choose ALL that apply.

A. \(x^3\)

B. \(\sqrt[3]{x}\)

C. \(x^2+x\)

D. \(x^2-x^3\)

E. \(1+2x\)

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IlCreatore
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Re: Which of the following must be greater than x, where -1 < x [#permalink] New post   30 Oct 2017, 10:33
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I am ok with all the answers but C. If x = -(1/2), then x^2+x = 1/4-1/2 = -1/2 that is equal to x. So it is not true that x^2+x must be greater than x.

Am I right? Or am I just tired that I do not get why C is ok?
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achirarulz
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Re: Which of the following must be greater than x, where -1 < x [#permalink] New post   20 Feb 2018, 11:15
i don`t get why A is right.. can someone please explain?


Bunuel wrote:
Which of the following must be greater than x, where -1 < x < 0? Choose ALL that apply.

A. \(x^3\)

B. \(\sqrt[3]{x}\)

C. \(x^2+x\)

D. \(x^2-x^3\)

E. \(1+2x\)

Kudos for correct solution.

Show: :: OA
A, C, D, and E
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Re: Which of the following must be greater than x, where -1 < x [#permalink] New post   20 Feb 2018, 11:38
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Think x = 0.5 that is an exactly half way between -1 and zero.

-0.5 elevated to the third power becomes -0.125 that is on the number line is closer to zero than -0.5. Which means -0.125 is on the right side of -0.5


-1 ------------- -0.5 ----------------- - 0.125------------ zero

A is correct.

Hope this helps.

Regards
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achirarulz
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Re: Which of the following must be greater than x, where -1 < x [#permalink] New post   21 Feb 2018, 10:00
thanks :-D


Carcass wrote:
Think x = 0.5 that is an exactly half way between -1 and zero.

-0.5 elevated to the third power becomes -0.125 that is on the number line is closer to zero than -0.5. Which means -0.125 is on the right side of -0.5


-1 ------------- -0.5 ----------------- - 0.125------------ zero

A is correct.

Hope this helps.

Regards
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jelal123
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Re: Which of the following must be greater than x, where -1 < x [#permalink] New post   15 Jun 2019, 04:49
IlCreatore wrote:
I am ok with all the answers but C. If x = -(1/2), then x^2+x = 1/4-1/2 = -1/2 that is equal to x. So it is not true that x^2+x must be greater than x.

Am I right? Or am I just tired that I do not get why C is ok?


if x=-1/2
then x^2+x= (-1/2*-1/2)+ (-1/2)
= 1/4-1/2
= -1/4 [ as the LCM of 2 and 4 is 4)
So, -1/4>-1/2
So, C
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GreenlightTestPrep
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Re: Which of the following must be greater than x, where -1 < x [#permalink] New post   15 Jun 2019, 08:09
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IlCreatore wrote:
I am ok with all the answers but C. If x = -(1/2), then x^2+x = 1/4-1/2 = -1/2 that is equal to x. So it is not true that x^2+x must be greater than x.

Am I right? Or am I just tired that I do not get why C is ok?


You're just tired :)
1/4 - 1/2 = -1/4 (not -1/2)

Cheers,
Brent
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ademeutia
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Re: Which of the following must be greater than x, where -1 < x [#permalink] New post   23 Jul 2022, 08:40
Why B is incorrect?
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GreenlightTestPrep
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Which of the following must be greater than x, where -1 < x [#permalink] New post   23 Jul 2022, 09:52
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ademeutia wrote:
Why B is incorrect?


B. \(\sqrt[3]{x}\)

\(\sqrt[3]{-\frac{1}{8}} = -\frac{1}{2}\) and \(-\frac{1}{2} < -\frac{1}{8}\)
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