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A restaurant menu has several options for tacos. There are 3
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05 Aug 2018, 14:21
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A restaurant menu has several options for tacos. There are 3 types of shells, 4 types of meat, 3 types of cheese, and 5 types of salsa. How many distinct tacos can be ordered assuming that any order contains exactly one of each of the above choices?
Re: A restaurant menu has several options for tacos. There are 3
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07 Aug 2018, 06:02
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Explanation
This problem tests the fundamental counting principle, which states that the total number of choices is equal to the product of the independent choices. Therefore, the total number of tacos is (3) (4)(3)(5) = 180 tacos.
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Re: A restaurant menu has several options for tacos. There are 3
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09 Apr 2020, 09:44
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sandy wrote:
A restaurant menu has several options for tacos. There are 3 types of shells, 4 types of meat, 3 types of cheese, and 5 types of salsa. How many distinct tacos can be ordered assuming that any order contains exactly one of each of the above choices?
A restaurant menu has several options for tacos. There are 3
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06 Sep 2022, 21:27
A restaurant menu has several options for tacos. There are 3 types of shells, 4 types of meat, 3 types of cheese, and 5 types of salsa. How many distinct tacos can be ordered assuming that any order contains exactly one of each of the above choices?
We apply the fundamental counting principle which says that if there are \(n\) ways of doing something, and \(m\) ways of doing another thing after that, then there are \(n ∗ m\) ways to perform both of these actions.
In the above case \(3 * 4 * 3 * 5 = 180\) different types of tacos can be ordered.
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