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Re: Q02-38 Question # 08 Section # 09 [#permalink]
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Peter wrote:
Carcass wrote:
Hi,

well I have to admit that the explanation is not the top-notch but it is not wrong.

Starting from what we do know: X could be positive or negative: we do not know at the moment AND y is negative.

Now look at the first part of the equation \(\sqrt{x^2}\) is equal to |x|. From this we also know that |x| = -x. Which means that on the left hand side X is positive, always. On the right hand side for X to be always positive X must be negative. This are math rules that is better for you to know as cold during the exam.

As such, actually we do have that X/X is = 1 and is negative. So -1

Going to the second square root |y| = -y so -y * - y = y^2 that under square root becomes |y|.

At this point we have -1 - |y| AND we already know that |y| = -y .

-1 - (-y) = -1 +y

Hope is clear this. Waiting, though, math expert for further clarification.


I still don't know why \(\sqrt{\frac{-y}{|y|}}\) =-y NOT -1?



Consider y = (-2), as y<0. hence -y = -(-2) = 2.
|y| = |-2| = 2.
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Re: Q02-38 Question # 08 Section # 09 [#permalink]
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I was thinking another way. Let me correct if I am horribly wrong! Let x and y both equal -1. from the first, sqrt of (x square)/x we get -1 and also form second part we get -1. So adding, -2. Consider all options!. Option D fits!
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Re: Q02-38 Question # 08 Section # 09 [#permalink]
@AlaminMolla is correct. For ALL negative values of x and y, the expression will ALWAYS evaluate to be -2

So, the question is flawed. At the very least, the question should read "Which of the following COULD BE the value of ...", in which case A, D and E COULD equal -2

@arsh are you sure you transcribed the question correctly?

Cheers,
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Re: Q02-38 Question # 08 Section # 09 [#permalink]
this was hard to understand
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Re: Q02-38 Question # 08 Section # 09 [#permalink]
Hello from the GRE Prep Club BumpBot!

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