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Re: QOTD#14 When x is divided by 3, the remainder is 1. When x [#permalink]
1
in 1st case when N=4/3..remainder=1
2nd case when N=9/7...remainder=2
looking at condition we can conclude that 3,9,27,81.....in short, the power of 3 is increasing there and the limit is till 100 hence last number to consider is 81...making it total 4 numbers.
answer 4
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Re: QOTD#14 When x is divided by 3, the remainder is 1. When x [#permalink]
Given that When x is divided by 3, the remainder is 1. When x is divided by 7, the remainder is 2. And we need to find How many positive integers less than 100 could be values for x

Theory: Dividend = Divisor*Quotient + Remainder

When x is divided by 3, the remainder is 1

x -> Dividend
3 -> Divisor
a -> Quotient (Assume)
1 -> Remainders
=> x = 3*a + 1 = 3a + 1

When x is divided by 7, the remainder is 2

x -> Dividend
7 -> Divisor
b -> Quotient (Assume)
2 -> Remainders
=> x = 7*b + 2 = 7b + 2

x = 3a + 1 = 7b + 2
=> a = \(\frac{7b + 1}{3}\)

Only those values of b which will also give a as integer will give us the common values of x
b = 2, 5, 8, 11, 14,...
But for b = 14, we will get x = 7b + 2 = 7*14 + 2 = 100 which is NOT less than 100

=> 4 values of x less than 100 are possible

So, Answer will be 4
Hope it helps!

Watch the following video to learn the Basics of Remainders

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Re: QOTD#14 When x is divided by 3, the remainder is 1. When x [#permalink]
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