Explanation

To solve this question, plug in the answers as the number of seniors to see if the rest of the class adds up to 150.

Start with choice C. If S = 24, then \(\frac{60}{100}\) and J = 40; since 40 = 50% of F, then F = 80; since the sum of the students is 24 + 40 + 80 = 144, which is less than 150, try larger numbers and eliminate choices (A), (B), and (C).

For choice D, if S = 25, then \(25 = J \times \frac{60}{100}\), thus there are 41.67 juniors, which is incorrect since it is impossible to have a fraction of a student.

For choice (E), if S = 27, then \(J \times \frac{60}{100}\), thus J = 45; since 45 = 50% of F, then F = 90; since 27 + 45 + 90 = 162, which is at least 160, choice (E) is the only correct answer.

Hence option E is correct!