ExplanationTo solve this question, plug in the answers as the number of seniors to see if the rest of the class adds up to 150.
Start with choice C. If S = 24, then \(\frac{60}{100}\) and J = 40; since 40 = 50% of F, then F = 80; since the sum of the students is 24 + 40 + 80 = 144, which is less than 150, try larger numbers and eliminate choices (A), (B), and (C).
For choice D, if S = 25, then \(25 = J \times \frac{60}{100}\), thus there are 41.67 juniors, which is incorrect since it is impossible to have a fraction of a student.
For choice (E), if S = 27, then \(J \times \frac{60}{100}\), thus J = 45; since 45 = 50% of F, then F = 90; since 27 + 45 + 90 = 162, which is at least 160, choice (E) is the only correct answer.
Hence option E is correct!
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