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Rectangle A has a length of 12 inches and a width of 5 inche

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Carcass
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Rectangle A has a length of 12 inches and a width of 5 inche [#permalink] New post   21 Oct 2018, 08:36
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Rectangle A has a length of 12 inches and a width of 5 inches. Rectangle B has a length of 9 inches and a width of 10 inches. By what number must the area of rectangle A be multiplied in order to get the area of rectangle B?

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Re: Rectangle A has a length of 12 inches and a width of 5 inche [#permalink] New post   21 Oct 2018, 19:12
Carcass wrote:
Rectangle A has a length of 12 inches and a width of 5 inches. Rectangle B has a length of 9 inches and a width of 10 inches. By what number must the area of rectangle A be multiplied in order to get the area of rectangle B?

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The area of rectangle A = 12 * 5 =60


The area of rectangle B = 9 * 10 = 90

Therefore the number multiplied to rectangle A to obtain the area of rectangle B = \(\frac{90}{60}= 1.5\)
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Rectangle A has a length of 12 inches and a width of 5 inche [#permalink] New post   16 Mar 2019, 00:40
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Rectangle A has a length of 12 inches and a width of 5 inches. Rectangle B has a length of 9 inches and a width of 10 inches. By what number must the area of rectangle A be multiplied in order to get the area of rectangle B?

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Re: Rectangle A has a length of 12 inches and a width of 5 inche [#permalink] New post   20 Mar 2019, 16:33
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The area of a rectangle is equal to the length times the width. So the area of rectangle A is 12*5 = 60 and the area of rectangle B is 9*10 = 90.

By what number to we have to multiply 60 by to get 90? Using algebra:

60x = 90

Divide both sides by 60:

x = 90/60 = 1.5

And indeed, when we multiply 60 by 1.5, we get 90.
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Re: Rectangle A has a length of 12 inches and a width of 5 inche [#permalink] New post   06 Jan 2022, 09:37
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