Qt A

\(567213560\) when divided by \(8\)

\(8\)'s divisibility rule:
if the last three digits are divisible by \(8\), then the whole number is divisible by \(8\)

consider the last three digits \(560\), when divided by \(8\), the remainder will be \(0\)

Qt B

\(297845786\) when divided by \(7\)

\(7\)'s divisibility rule:
Take the last digit of the number you're testing and double it. Subtract this number from the rest of the digits in the original number. If this new number is either \(0\) or if it's a number that's divisible by \(7\), then you know that the original number is also divisible by \(7\).

Here, the last digit is \(6\), and its double is \(12\).

When subtracting \(12\) from \(29784578\), we will get \(29784566\), which is divisible by \(7\).

You can use the calculator as well.

Qt A = Qt B

Answer C
_________________

Can anyone elaborate this question? Is the answer A or C?

The solution requires the use of divisibility rules of 7 and 8. We get the remainders equal to zero for both quantities. Hence the answer is C. You may want to see the detailed solution shared by rx10
_________________

Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.