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Runners $x$ and $y$ started an 18-mile race at the same time. Runner $
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23 Apr 2025, 00:43
23 Apr 2025, 00:43
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Runners $x$ and $y$ started an 18-mile race at the same time. Runner $x$ completed the course in 6 hours, and runner $y$ finished 2 hours earlier. How many miles per hour did runner $y$ run faster than runner $x$ ?
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1.5
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Re: Runners $x$ and $y$ started an 18-mile race at the same time. Runner $
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27 Apr 2025, 04:45
27 Apr 2025, 04:45
Expert Reply
Let the speeds of runners $\(x\)$ and $\(y\)$ be $\(S_x\)$ and $\(S_y\)$ respectively. Therefore, $\(S_y-S_x=\frac{18}{4}-\frac{18}{6}=\frac{9}{2}-\frac{9}{3}=\frac{27-18}{6}=\frac{9}{6}=\frac{3}{2}=1.5\)$. Thus, the correct answer is 1.5 .
gmatclubot
Re: Runners $x$ and $y$ started an 18-mile race at the same time. Runner $ [#permalink]
27 Apr 2025, 04:45
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