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S=1-1/2+1/3+1/4+1/5+1/6+1/7+1/8+1/9-1/10
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21 Aug 2021, 08:45
21 Aug 2021, 08:45
Expert Reply
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Question Stats:
79% (01:17) correct
20% (00:59) wrong based on 53 sessions
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\(S=1-\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}-\frac{1}{10}\)
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(S\) |
\(\frac{1}{2}\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
S=1-1/2+1/3+1/4+1/5+1/6+1/7+1/8+1/9-1/10
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21 Aug 2021, 08:50
21 Aug 2021, 08:50
1
This can be done without lifting a pen, if read carefully
\(S=1-\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}-\frac{1}{10}\)
\(S = (1 - \frac{1}{2}) + \frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+ (\frac{1}{9}-\frac{1}{10})\)
\(S = \frac{1}{2} + \frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{90}\)
So it will always be > \(\frac{1}{2}\)
Qt A > Qt B
Answer A
\(S=1-\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}-\frac{1}{10}\)
\(S = (1 - \frac{1}{2}) + \frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+ (\frac{1}{9}-\frac{1}{10})\)
\(S = \frac{1}{2} + \frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{90}\)
So it will always be > \(\frac{1}{2}\)
Qt A > Qt B
Answer A
General Discussion
Re: S=1-1/2+1/3+1/4+1/5+1/6+1/7+1/8+1/9-1/10
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21 Aug 2021, 08:59
21 Aug 2021, 08:59
1
Expert Reply
Pure horsepower
