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Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Set A = {22, 27, 11, 12, 2}, and set B: {14, 19, 3, 4, x}
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15 Jul 2019, 16:22
15 Jul 2019, 16:22
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Set A = {22, 27, 11, 12, 2}, and set B: {14, 19, 3, 4, x}
If x < 0, and the standard deviation of set A = the standard deviation of set B, what is the value of x?
A) -2
B) -3
C) -4
D) -5
E) -6
If x < 0, and the standard deviation of set A = the standard deviation of set B, what is the value of x?
A) -2
B) -3
C) -4
D) -5
E) -6
Re: Set A = {22, 27, 11, 12, 2}, and set B: {14, 19, 3, 4, x}
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15 Jul 2019, 20:13
15 Jul 2019, 20:13
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Set A = {22, 27, 11, 12, 2}, and set B: {14, 19, 3, 4, x}
Difference of elements between SET A and SET B = 22-14 = 8, 27-19=8, 11-3=8, 12-4=8, 2-x = 8
If S.D is same for both SET A and SET B and SET B elements are 8 less than SET A elements, the difference in mean is also equal and the difference in the last terms (between SET A and SET B) should also be 8, i.e.
2-x = 8 => x = -6
Further, mean of SET A = 14.8, mean of SET B = (40+x)/5 => which value of x will give me a difference in mean of 8, only x = -6
(40-6)/5 = 6.8 => 14.8 - 6.8 = 8 (Difference of means between SET A and SET B). Hope this helps.
Warm regards,
Karthik
Difference of elements between SET A and SET B = 22-14 = 8, 27-19=8, 11-3=8, 12-4=8, 2-x = 8
If S.D is same for both SET A and SET B and SET B elements are 8 less than SET A elements, the difference in mean is also equal and the difference in the last terms (between SET A and SET B) should also be 8, i.e.
2-x = 8 => x = -6
Further, mean of SET A = 14.8, mean of SET B = (40+x)/5 => which value of x will give me a difference in mean of 8, only x = -6
(40-6)/5 = 6.8 => 14.8 - 6.8 = 8 (Difference of means between SET A and SET B). Hope this helps.
Warm regards,
Karthik
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: Set A = {22, 27, 11, 12, 2}, and set B: {14, 19, 3, 4, x}
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18 Jul 2019, 11:58
18 Jul 2019, 11:58
2
GreenlightTestPrep wrote:
Set A = {22, 27, 11, 12, 2}, and set B: {14, 19, 3, 4, x}
If x < 0, and the standard deviation of set A = the standard deviation of set B, what is the value of x?
A) -2
B) -3
C) -4
D) -5
E) -6
If x < 0, and the standard deviation of set A = the standard deviation of set B, what is the value of x?
A) -2
B) -3
C) -4
D) -5
E) -6
The test-makers like to test the following concept: If we take a set of numbers with a Standard Deviation of X and add k to each value in the set, the resulting set will still have a Standard Deviation of X.
This should make sense, since Standard Deviation is a measurement of dispersion (i.e., how dispersed the numbers are)
For example, if we take the set {1,2,3} and add 15 to each set member, we get {16, 17, 18}
In both sets, the second number is 1 greater than the first number, and the third number is 1 greater than the second number.
As such, both sets have the same Standard Deviation.
Likewise, if we take the set {7,7,17} and add 11 to each set member, we get {18, 18, 28}
In both sets, the first two numbers are the same, and the third number is 10 greater than the other two numbers.
As such, both sets have the same Standard Deviation.
If we arrange both sets in ascending order we get:
Set A = {2, 11, 12, 22, 27}
Set B = {x, 3, 4, 14, 19}
Notice that each of the 4 biggest numbers in set A are 8 greater than each of the 4 biggest numbers in set B
For example, 27 = 19 + 8
And 27 = 19 + 8
And 22 = 14 + 8
And 12 = 4 + 8
And 11 = 3 + 8
Since the two sets have the same Standard Deviation, it must be the case that 2 = x + 8
Solve for x to get: x = -6
Answer: E
Cheers,
Brent
