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Re: Set A consists of 350 consecutive multiples of 2. Set B cons
[#permalink]
30 Sep 2026, 06:04
30 Sep 2026, 06:04
take the 50th as starting point => 50th A - 50th B = 199.5, just call 50th A = a and 50th B = b for short
a - b = 199.5
30th of A is 105 which is 70 elements away from a so its about 140 from a
70th of B is 140 which is 40 elements away from b so its about 120 from b
now combine everything we have:
30th A - 70th B = (a - 140) - (b + 120) = a - b -260 since a - b = 199.5 the result of this subtraction is negative so 70th B should be greater than 30th of A
a - b = 199.5
30th of A is 105 which is 70 elements away from a so its about 140 from a
70th of B is 140 which is 40 elements away from b so its about 120 from b
now combine everything we have:
30th A - 70th B = (a - 140) - (b + 120) = a - b -260 since a - b = 199.5 the result of this subtraction is negative so 70th B should be greater than 30th of A
gmatclubot
Re: Set A consists of 350 consecutive multiples of 2. Set B cons [#permalink]
30 Sep 2026, 06:04
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