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Set Q consists of 6 consecutive even integers beginning with -4, and S
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12 Aug 2021, 07:24
12 Aug 2021, 07:24
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Set Q consists of 6 consecutive even integers beginning with -4, and Set P consists of 4 consecutive odd integers beginning with 1. If Set M consists of all numbers from both Set P and Set Q, how much greater is the median of Set M than the mean of Set M?
A. 3
B. 2.5
C. 0.8
D. 0.3
E. 0.25
A. 3
B. 2.5
C. 0.8
D. 0.3
E. 0.25
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Re: Set Q consists of 6 consecutive even integers beginning with -4, and S
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12 Aug 2021, 07:29
12 Aug 2021, 07:29
1
Carcass wrote:
Set Q consists of 6 consecutive even integers beginning with -4, and Set P consists of 4 consecutive odd integers beginning with 1. If Set M consists of all numbers from both Set P and Set Q, how much greater is the median of Set M than the mean of Set M?
A. 3
B. 2.5
C. 0.8
D. 0.3
E. 0.25
A. 3
B. 2.5
C. 0.8
D. 0.3
E. 0.25
Set Q: {-4, -2, 0, 2, 4, 6}
Set P: {1, 3, 5, 7}
So, set M = {-4, -2, 0, 1, 2, 3, 4, 5, 6, 7}
Median of set M: Since set M has an EVEN number of values, the median is equal to the mean of the 2 middlemost values.
{-4, -2, 0, 1, 2, 3, 4, 5, 6, 7}
So, the median of set M = (2 + 3)/2 = 5/2 = 2.5
Mean of set M = [(-4) + (-2) + 0 + 1 + 2 + 3 + 4 + 5 + 6 + 7]/10 = 22/10 = 2.2
How much greater is the median of Set M than the mean of Set M?
2.5 - 2.2 = 0.3
Answer: D
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Re: Set Q consists of 6 consecutive even integers beginning with -4, and S [#permalink]
12 Aug 2021, 07:29
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