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Re: Set X consists of 100 numbers. The average (arithmetic mean) of set
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24 Jun 2026, 06:05
Explanation
Let the original set have:
n=100
mean=10
standard deviation=4.6
The standard deviation measures spread around the mean. To decrease the standard deviation as much as possible when adding one number, we want to add a value that is as close as possible to the current mean.
The current sum of squared deviations is
\(100(4.6)^2=2116.\)
If a number x is added, the new variance depends on (x−10)^2. The smaller (x−10)^2 is, the more the standard deviation decreases.
Therefore, among the two choices, compute each distance from 10: \(∣x_{1}-10∣ and ∣x_{2} -10∣.\)
The number closer to 10 will produce the greater decrease in standard deviation.
Answer: E