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Shaundra drove the same route to work each morning, Monday through...
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Updated on: 29 Apr 2023, 10:15
Updated on: 29 Apr 2023, 10:15
00:00
Question Stats:
50% (02:10) correct
50% (01:15) wrong based on 12 sessions
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Shaundra drove the same route to work each morning, Monday through Friday, in a particular week. On Monday and Tuesday she averaged 20 miles per hour, and on her three remaining work days she averaged 30 miles per hour.
A Quantity A is greater.
B Quantity B is greater.
C The two quantities are equal.
D The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
Shaundra’s average speed for all five morning commutes |
26 miles per hour |
A Quantity A is greater.
B Quantity B is greater.
C The two quantities are equal.
D The relationship cannot be determined from the information given.
Originally posted by thelastzedi on 29 Apr 2023, 09:10.
Last edited by Carcass on 29 Apr 2023, 10:15, edited 1 time in total.
Last edited by Carcass on 29 Apr 2023, 10:15, edited 1 time in total.
Fixed
Re: Shaundra drove the same route to work each morning, Monday through...
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29 Apr 2023, 10:17
29 Apr 2023, 10:17
Expert Reply
Please follow the rules for posting https://gre.myprepclub.com/forum/rules- ... -1083.html
This is a QCQ NOT a problem solving. Please post under the right sub-forum. which is this
Thank you
_________________
This is a QCQ NOT a problem solving. Please post under the right sub-forum. which is this
Thank you
_________________
Re: Shaundra drove the same route to work each morning, Monday through...
[#permalink]
29 Apr 2023, 10:38
29 Apr 2023, 10:38
Expert Reply
You here cannot use the weighted average because you do not have the speed of the two distances. You do not know if she drove fast o slowly the first two days or the other three days
You have only the miles for 5 days
2d/20+3d/30=2d/10=d/5
5d/d/5=25d/d=25
B is bigger
_________________
You have only the miles for 5 days
2d/20+3d/30=2d/10=d/5
5d/d/5=25d/d=25
B is bigger
_________________
Re: Shaundra drove the same route to work each morning, Monday through...
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30 Apr 2023, 12:11
30 Apr 2023, 12:11
1
Carcass wrote:
You here cannot use the weighted average because you do not have the speed of the two distances. You do not know if she drove fast o slowly the first two days or the other three days
You have only the miles for 5 days
2d/20+3d/30=2d/10=d/5
5d/d/5=25d/d=25
B is bigger
You have only the miles for 5 days
2d/20+3d/30=2d/10=d/5
5d/d/5=25d/d=25
B is bigger
yes,
i have tried this way as well. i got this ans.
by the way "you do not have the speed of the two distances"
actually we have given
for mon & tues - 20miles/H
remaining 3 days - 30 miles/H
Re: Shaundra drove the same route to work each morning, Monday through...
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31 Aug 2023, 18:37
31 Aug 2023, 18:37
1
can we use the formula 2*S1*S2/S1+S2, THE FORMULA THAT IS USED WHILE THE DISTANCE IS SAME
BASED ON WHICH I GOT 2*30*20/20+30 = 1200/50 = 24
24<26
SO B IS GREATER
BASED ON WHICH I GOT 2*30*20/20+30 = 1200/50 = 24
24<26
SO B IS GREATER
Re: Shaundra drove the same route to work each morning, Monday through...
[#permalink]
05 Sep 2023, 14:53
05 Sep 2023, 14:53
1
There is no specified distance, so if you make up a random distance (I chose 60 miles), you can solve the problem this way. If the route to work is 60 miles, the average speed for Monday and Tuesday would be d/t = r or 2(60)/t = 20. Therefore for Monday and Tuesday, the time would be 6 hours.
It's the same for Weds, Thurs and Friday. Using d/t = r, it would be 3(60)/t = 30. Therefore time would also be 6 hours.
For the last part, the total distance 60(5) divided by the total time 12 hrs = 300/12 or 25 miles per hour.
25 < 26 meaning Choice B is the correct answer.
It's the same for Weds, Thurs and Friday. Using d/t = r, it would be 3(60)/t = 30. Therefore time would also be 6 hours.
For the last part, the total distance 60(5) divided by the total time 12 hrs = 300/12 or 25 miles per hour.
25 < 26 meaning Choice B is the correct answer.
gmatclubot
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