GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Six beads, each a different color, are put into a bag. How
[#permalink]
19 Oct 2017, 01:19
19 Oct 2017, 01:19
00:00
Question Stats:
72% (00:41) correct
27% (00:36) wrong based on 11 sessions
Hide Show timer Statistics
Six beads, each a different color, are put into a bag. How many different three-color combinations are possible if 3 beads are drawn out of the bag simultaneously? (Assume the order of the colors does not matter.)
(A) 6
(B) 9
(C) 18
(D) 20
(E) 120
Kudos for correct solution.
(A) 6
(B) 9
(C) 18
(D) 20
(E) 120
Kudos for correct solution.
Re: Six beads, each a different color, are put into a bag. How
[#permalink]
19 Oct 2017, 01:30
19 Oct 2017, 01:30
1
Since the order does not matter we are talking about combinations. Then, the problem is solved by computing \(\frac{6!}{3!3!} = \frac{6*5*4}{2*3} = 20\).
Answer D
Answer D
gmatclubot
Re: Six beads, each a different color, are put into a bag. How [#permalink]
19 Oct 2017, 01:30
Moderators:
