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Re: Six students are equally divided into 3 groups, then, the three groups [#permalink]
1
monkeyrabbit wrote:
The official answer to this question is wrong.
NO of ways to divide 6 students in 3 pairs is 6C2 x 4C2 x 2C2 = 6C2 X 4C2 X 1 = 90
No of ways to assign the teams 3 assignments = 3!
Ans (E) 540

verified on google.



When you did 6C2 x 4C2 x 2C2 = 6C2 X 4C2 X 1 = 90. You took care of all the possible arrangements as well. Hence, answer would be 90 only.
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Re: Six students are equally divided into 3 groups, then, the three groups [#permalink]
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