Re: Smith bought a set of six bottles of different sizes at a total price
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01 Feb 2024, 03:53
The answers are E and G.
Since the difference between the price of each bottle is constant ($d), we are dealing an arithmetic progression here.
Let the price of the smallest bottle = s
--> Price of the other bottles --> s + d, s + 2d, s + 3d, s + 4d, s + 5d
--> Total --> $75 = s + (s + d) + (s + 2d) + (s + 3d) + (s + 4d) + (s + 5d)
--> 6s + 15d = 75
Check values for s:
If s = 1, 6*1 + 15d = 75 --> 15d = 69 (not possible)
If s = 2, 6*2 + 15d = 75 --> 15d = 63 (not possible)
If s = 3, 6*3 + 15d = 75 --> 15d = 57 (not possible)
If s = 4, 6*4 + 15d = 75 --> 15d = 51 (not possible)
If s = 5, 6*5 + 15d = 75 --> 15d = 45 (possible)
If s = 8, 6*8 + 15d = 75 --> 15d = 27 (not possible)
If s = 10, 6*10 + 15d = 75 --> 15d = 15 (possible)