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Solution Y is 30 percent liquid X and 70 percent water. If
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05 Feb 2020, 07:38
05 Feb 2020, 07:38
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54% (02:08) correct
45% (01:14) wrong based on 11 sessions
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Solution Y is 30 percent liquid X and 70 percent water. If 2 kilograms of water evaporate from 8 kilograms of solution Y and 2 kilograms of solution Y are added to the remaining 6 kilograms of liquid, what percent of this new solution is liquid X ?
(A) 30%
(B) 33 1/3 %
(C) 37.5 %
(D) 40%
(E) 50%
(A) 30%
(B) 33 1/3 %
(C) 37.5 %
(D) 40%
(E) 50%
Re: Solution Y is 30 percent liquid X and 70 percent water. If
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06 Feb 2020, 00:10
06 Feb 2020, 00:10
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Asif123 wrote:
Solution Y is 30 percent liquid X and 70 percent water. If 2 kilograms of water evaporate from 8 kilograms of solution Y and 2 kilograms of solution Y are added to the remaining 6 kilograms of liquid, what percent of this new solution is liquid X ?
(A) 30% (B) 33 1/3 % (C) 37.5 % (D) 40% (E) 50%
(A) 30% (B) 33 1/3 % (C) 37.5 % (D) 40% (E) 50%
Let’s denote X as number of liquid X parts in 1 liter of solution Y
Let’s denote W as number of parts of water in 1 liter of solution Y
Initially we have:
0.3x + 0.7w for one kilogram of solution Y or:
2.4x + 5.6w for 8 kilograms of solution Y
Evaporating 2 kg of water results in:
2.4x + 3.6w
Adding 2kg of solution Y means adding (0.6x +1.4 w) to (2.4x + 3.6w)
The final composition of mixture is:
3x + 5w
The percentage of liquid x is: 3/ (3+5) = 3/8 =37.5%
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Solution Y is 30 percent liquid X and 70 percent water. If
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11 Apr 2021, 12:08
11 Apr 2021, 12:08
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Asif123 wrote:
Solution Y is 30 percent liquid X and 70 percent water. If 2 kilograms of water evaporate from 8 kilograms of solution Y and 2 kilograms of solution Y are added to the remaining 6 kilograms of liquid, what percent of this new solution is liquid X ?
(A) 30%
(B) 33 1/3 %
(C) 37.5 %
(D) 40%
(E) 50%
(A) 30%
(B) 33 1/3 %
(C) 37.5 %
(D) 40%
(E) 50%
Solution Y = \(8\) kg
Liq. X to Water = \(3 : 7\)
Liq. X = \(\frac{3}{(3 + 7)}(8) = 2.4\) Kg
Water = \(\frac{7}{(3 + 7)}(8) = 5.6\) kg
After the water evaporated;
Liq. X = \(2.4\) kg
Water = \(5.6 - 2 = 3.6\) kg
In \(2\) kg Solution Y;
Liq. X added \(= \frac{3}{(3 + 7)}(2) = 0.6\) kg
Water added \(= \frac{7}{(3 + 7)}(2) = 1.4\) kg
After adding Solution Y;
Total Liq. X \(= 2.4 + 0.6 = 3\) kg
Total Water \(= 3.6 + 1.4 = 5\)kg
Liq. X \(= \frac{3}{(3 + 5)}(100) = 37.5\)%
Hence, option C
